|
Mean
 |
The average
of all data entries.
|
 |
Measure of
central tendency for
normally distributed data.
|
 |
DO NOT
calculate a mean from values
that are already averages.
|
 |
DO NOT
calculate a mean of ratios
or percentages for groups of
several difference sizes; go
back to the raw data and
recalculate.
|
 |
DO NOT
calculate a mean when the
measurement scale is not
linear (i.e. pH units are
not measured on a linear
scale).
|
 |
The sum of
all the results divided by
the number of results.
|
Standard Deviation
Averages do not tell us everything
about a sample. Samples can be very
uniform with the data all bunched
around the mean or they can be
spread out a long way from the mean.
The statistic that measures this
spread is called the standard
deviation.
The
wider the spread of scores, the
larger the standard deviation.
For
data that has a normal distribution,
68% of the data lies within one
standard deviation of the mean.

Calculate the standard deviation by
subtracting the mean of a
distribution from the value of each
individual variable in the
distribution, squaring each
resulting difference, summing these
squared differences, then dividing
this sum by the number of variables,
and finally taking the square root
of this quotient.

S = standard
deviation
Σ = sum of
X = individual score
M = mean of all scores
n = sample size (number of scores)
Example:
Given the set of numbers {20.0,
23.0, 25.0, 26.0}, calculate the
mean and the standard deviation.
Mean =
(20+23+25+26)/4 = 23.5
Standard
deviation
1.
Calculate (X-M)
a.
The mean of
these numbers was found to
be equal to 23.5.
b.
The
deviations from the mean are
respectively:
·
20.0 - 23.5 =
-3.5
·
23.0 - 23.5 =
-0.5
·
25.0 - 23.5 =
1.5
·
26.0 - 23.5 =
2.5
2.
Square each of
these deviations to determine
(X-M)2
·
(3.5)2
= 12.25
·
(0.5)2=
0.25
·
(1.5)2=
2.25
·
(2.5)2=
6.25
3.
Add the values
from step 2 together to get
∑(X-M)2
·
12.25 + 0.25
+ 2.25 + 6.25 = 21.
4.
Calculate (n-1)
by subtracting 1 from your
sample size
·
Since the
were 4 original numbers, our
n=4
·
Therefore
(n-1) = 3
5.
Divide the answer
from step 3 by the answer from
step 4 to find
∑(X-M)2
n-1
·
21 / 3 = 7
6.
Calculate the
square root of your answer from
step 5 to determine the standard
deviation!

·
The square
root of 7 is approximately
2.65 which rounds to 2.7
7.
Answer: the
standard deviation of the set of
numbers {20, 23, 25, 26} is
2.7. This means that 68% of the
data lies within 2.65 of the
mean (68% of the values are
equal to 23.5 +/- 2.65).
Using EXCEL to calculate the mean
and the standard deviation
Type the values you
are trying to find the mean for in a
column. You can label the column,
but you don’t have to.
Determine
which box you want the mean
to appear in. In the example, I
want the mean to appear in box A12.
In that box, type:
=AVERAGE(A2:A11)
and then hit enter.
Basically you are telling Excel to
average boxes A2 through A11.
Determine which box
you want the standard deviation to
appear in. In the example, I want
the standard deviation to appear in
box A13. In that box, type:
=STDEV(A2:A11) and then hit
enter. You are giving Excel
the box labels for the data for
which you want to find the standard
deviation.
| |
A |
|
1 |
Number of Pennies |
|
2 |
134 |
|
3 |
130 |
|
4 |
136 |
|
5 |
132 |
|
6 |
131 |
|
7 |
137 |
|
8 |
131 |
|
9 |
135 |
|
10 |
130 |
|
11 |
129 |
|
12 |
132.5 |
|
13 |
2.798809 |
Calculating mean and
standard deviation on the
TI-83:
First we have to
enter the data. Hit the STAT button
and you will see the options EDIT,
CALC and TESTS atop the screen. Use
the left and right arrows (if
necessary) to move the cursor to
EDIT, then select 1:Edit...
Now
you will see a table with the
headings L1 and L2.
Enter the values under L1
(if you want to clear pre-existing
data first, move the cursor to the
top of the column, hit CLEAR and
then ENTER.)
Once all the data is
entered, go back to the STAT menu,
but this time move the cursor to
CALC instead of EDIT.
Once you're in the
CALC menu, select 1-Var Stats,
then hit ENTER.
The calculator will
display the x-mean, some
other stuff, and then the standard
deviation (sx).
Note that sx is
what we called s.d. in class;
the calculator refers to it as sx.
This is followed by something called
sigma x (which is
what you would get as standard
deviation if you had used n
instead of n-1), and finally
the sample size.
T-Test
A t-test is used to
determine if the means of two
samples (often an experimental and a
control group) are truly, or at
least significantly, different or if
the difference between them is
plausibly due to random variation
not related to the hypothesis being
tested.

The formula for the
t-test is a ratio. The top part of
the ratio is the difference between
the two means or averages. The
bottom part is a measure of the
variability of the data.
|
Sample 1 |
Sample 2 |
|
7.85 |
12.50 |
|
8.51 |
12.94 |
|
13.66 |
6.26 |
|
11.03 |
6.10 |
|
6.59 |
13.19 |
|
8.04 |
10.74 |
|
14.16 |
6.06 |
|
8.13 |
12.53 |
|
6.79 |
15.45 |
|
11.06 |
15.64 |
|
5.83 |
15.19 |
|
10.73 |
14.93 |
|
6.68 |
7.94 |
|
5.02 |
8.28 |
|
10.37 |
12.65 |
Let’s us an example
to help you learn the t-test:
Step 1:
Find the means for each sample
Sample 1 mean =
8.96
Sample 2
mean =
11.36
Step 2:
Find the absolute value of the
difference between the means.
This is
the top part of the t-test formula.
Mean 1 –
mean 2 =
X1
– x2 =
8.96 –
11.36 =
-2.40
Absolute
value =
2.40
Step 3:
The bottom part is called the
standard error of the
difference.
To compute it, first find the
standard deviation for each sample.
Sample 1
SD = 2.76
Sample 2
SD = 3.55
Step 4:
Square the standard deviation for
each group to find the “variance”
for each group.
Sample 1
variance = (2.76)2 =
7.63
Sample 1
variance = (3.55)2 =
12.57
Step
5:
Divide each squared standard
deviation by the sample size of that
group.
Sample
1: 7.63 / 15 =
0.51
Sample
2: 12.57 / 15 =
0.84
Step
6:
Add these two values
0.51 +
0.84 = 1.35
Step
7:
Take the square root of the number
to find the “standard
error of the difference”
√1.35 =
1.16
Step
8:
divide the difference in the means
(step 2) by the
standard error of the
difference (step 7)

T = 2.40
/ 1.16 =
2.07
Step 9:
You need to determine the degrees of
freedom (df) for the test. In the
t-test, the degrees of freedom is
the sum of the sample sizes of both
groups minus 2.

DF = (15
+15) – 2 =
28
Step 10:
Once you compute the
t-value (answer from step 8) and the
degrees of freedom (answer from step
9) you have to look it up in a table
of significance to test whether the
ratio is large enough to say that
the difference between the groups is
not likely to have been a chance
finding. To test the significance,
you need to set a risk level (called
the alpha level). In most research,
the "rule of thumb" is to set the
alpha level at .05. This means that
five times out of a hundred you
would find a statistically
significant difference between the
means even if there was none (i.e.,
by "chance").
Given the alpha
level, the df, and the t-value, you
can look the t-value up in a
standard table of significance to
determine whether the t-value is
large enough to be significant.

|
df |
.10 |
.05 |
.025 |
.01 |
.005 |
.000 |
|
1 |
3.078 |
6.314 |
12.706 |
31.821 |
63.657 |
636.619 |
|
2 |
1.886 |
2.920 |
4.303 |
6.965 |
9.925 |
31.598 |
|
3 |
1.638 |
2.353 |
3.182 |
4.541 |
5.841 |
12.941 |
|
4 |
1.533 |
2.132 |
2.776 |
3.747 |
4.604 |
8.610 |
|
5 |
1.476 |
2.015 |
2.571 |
3.365 |
4.032 |
6.859 |
|
6 |
1.440 |
1.943 |
2.447 |
3.143 |
3.707 |
5.959 |
|
7 |
1.415 |
1.895 |
2.365 |
2.998 |
3.499 |
5.405 |
|
8 |
1.397 |
1.860 |
2.306 |
2.896 |
3.355 |
5.041 |
|
9 |
1.383 |
1.833 |
2.262 |
2.821 |
3.250 |
4.781 |
|
10 |
1.372 |
1.812 |
2.228 |
2.764 |
3.169 |
4.587 |
|
11 |
1.363 |
1.796 |
2.201 |
2.718 |
3.106 |
4.437 |
|
12 |
1.356 |
1.782 |
2.179 |
2.681 |
3.055 |
4.318 |
|
13 |
1.350 |
1.771 |
2.160 |
2.650 |
3.012 |
4.221 |
|
14 |
1.345 |
1.761 |
2.145 |
2.624 |
2.977 |
4.140 |
|
15 |
1.341 |
1.753 |
2.131 |
2.602 |
2.947 |
4.073 |
|
16 |
1.337 |
1.746 |
2.120 |
2.583 |
2.921 |
4.015 |
|
17 |
1.333 |
1.740 |
2.110 |
2.567 |
2.898 |
3.965 |
|
18 |
1.330 |
1.734 |
2.101 |
2.552 |
2.878 |
3.922 |
|
19 |
1.328 |
1.729 |
2.093 |
2.539 |
2.861 |
3.883 |
|
20 |
1.325 |
1.725 |
2.086 |
2.528 |
2.845 |
3.850 |
|
21 |
1.323 |
1.721 |
2.080 |
2.518 |
2.831 |
3.819 |
|
22 |
1.321 |
1.717 |
2.074 |
2.508 |
2.819 |
3.792 |
|
23 |
1.319 |
1.714 |
2.069 |
2.500 |
2.807 |
3.767 |
|
24 |
1.318 |
1.711 |
2.064 |
2.492 |
2.797 |
3.745 |
|
25 |
1.316 |
1.708 |
2.060 |
2.485 |
2.787 |
3.725 |
|
26 |
1.315 |
1.706 |
2.056 |
2.479 |
2.779 |
3.707 |
|
27 |
1.314 |
1.703 |
2.052 |
2.473 |
2.771 |
3.690 |
|
28 |
1.313 |
1.701 |
2.048 |
2.467 |
2.763 |
3.674 |
|
29 |
1.311 |
1.699 |
2.045 |
2.462 |
2.756 |
3.659 |
|
30 |
1.310 |
1.697 |
2.042 |
2.457 |
2.750 |
3.646 |
|
40 |
1.303 |
1.684 |
2.021 |
2.423 |
2.704 |
3.551 |
|
60 |
1.296 |
1.671 |
2.000 |
2.390 |
2.660 |
3.460 |
|
120 |
1.289 |
1.658 |
1.980 |
2.358 |
2.617 |
3.373 |
|
c |
1.282 |
1.645 |
1.960 |
2.326 |
2.576 |
3.291 |
|
If your
calculated t value is
greater than the number in
the table, you can conclude
that the difference between
the means for the two groups
is significantly different.
|
In our example, the
number in the table for our data is
1.701. So, since our calculated
value (2.07) is greater than then
number in the table, we must
conclude that the difference between
the two groups IS SIGNIFICANTLY
DIFFERENT.
To check your answers
Sometimes it is nice
to check your answers to make sure
you are doing the calculations
right. Use
this
website to check your
results
Performing a
t-test with Excel
Excel calculates a
T-test in a slightly different way.
Rather than giving you the t value
and comparing it to a table, Excel
simply tells you the probability
that the means are different simply
due to chance. This is called a “P
value.”
Follow these steps to
calculate a P value using a t-test
with Excel:
Step 1:
Create two columns, side by side,
for the data of interest. Each
sample’s data should be in separate
columns like in the example above.
Step 2:
Click on another
blank cell where you wish the P
value to appear.
Step 3:
Then click “fx” on the Excel toolbar
and choose “statistical” from the
“function” list, then “TTest” from
the list.
Step 4:
Set the t-test parameters:
-
For “Array1”
highlight the data from one
sample; for “Array2”,
highlight the data in the
second column.
-
Enter “2” in
the box for “Tails.”
-
Lastly, you
will have to select the
“Type” of t-test. or our
purposes type “2.”
-
After
answering these questions
click “OK” and the P value
will appear. The P value
will fall between zero and
one.
Step 5: What does my P value
mean?
Using Excel with the same data from
the sample given above, Excel gives
the number 0.05. This means that
there is a 5% chance that the
differences between the two samples
are due to random chance alone.
Another way to say this is that
there is a 95% chance that the
difference between these two samples
is due to the variable being
investigated. Normally will say
that a P value of .05 or less is
significant.
Performing a
T-test
with the TI-83
1. Hit the STAT button on the
calculator
2. Select option 4 to clear any
past lists of data.
3. Select option 1 to EDIT your
lists.
4. Enter your data for each group
as List 1 and List 2
5. Hit STAT button and use the
arrow key to move over to the TESTS
option
6. Scroll down to option 4, the
2-sample T test and hit ENTER
7. Scroll to the bottom of the
screen and hit ENTER over the
CALCULATE option
8. Your results are given.
T =
calculated T value
df
= Degrees of Freedom
X1
= mean of list 1
X2
= mean of list 2
Sx1
= standard deviation of list 1
Sx2
= standard deviation of list 2
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